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Unread 01-20-2009, 10:47 PM   #1 (permalink)
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Solve this problem. Explain as completely as possible. Any answers that include math must show their work. No more than 500 words. Any number of pictures can be used as long as they are made by yourself. Do not search for the answer. Use reason.

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Unread 01-20-2009, 11:17 PM   #2 (permalink)
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Originally Posted by THEINCREDIBLEdork View Post
Solve this problem. Explain as completely as possible. Any answers that include math must show their work. No more than 500 words. Any number of pictures can be used as long as they are made by yourself. Do not search for the answer. Use reason.

Admissions until tomorrow at 10:00pm EST. Best answer wins internets.

You're a dipshit, the two triangles don't have the same dimensions. The top figure only looks like a triangle when it actually has four sides.

It's an optical illusion.
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Unread 01-20-2009, 11:20 PM   #3 (permalink)
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Originally Posted by DDTempest View Post
You're a dipshit, the two triangles don't have the same dimensions. The top figure only looks like a triangle when it actually has four sides.

It's an optical illusion.
Does not compute.
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Unread 01-20-2009, 11:21 PM   #4 (permalink)
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Does not compute.
He's right. You just don't see it because you aren't looking at it right.
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Unread 01-20-2009, 11:27 PM   #5 (permalink)
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I am not keen on geometry terms but the two smaller triangles APPEAR to be the same dimensions as the larger triangle. We'll use fractions to check.

Big "triangle" appears to be 5 squares tall by 13 squares long = 5/13
Green triangle is 2/5
Red triangle is 3/8

These triangles are not of equal dimensions, thus can't be a part of a larger triangle.
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Unread 01-20-2009, 11:45 PM   #6 (permalink)
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Originally Posted by DDTempest View Post
I am not keen on geometry terms but the two smaller triangles APPEAR to be the same dimensions as the larger triangle. We'll use fractions to check.

Big "triangle" appears to be 5 squares tall by 13 squares long = 5/13
Green triangle is 2/5
Red triangle is 3/8

These triangles are not of equal dimensions, thus can't be a part of a larger triangle.
I mean... I still don't see how you're anything but wrong here.
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Unread 01-20-2009, 11:50 PM   #7 (permalink)
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I mean... I still don't see how you're anything but wrong here.
That's ok, someone who is good at explaining geometry will come along and explain it soon enough.
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Unread 01-20-2009, 11:57 PM   #8 (permalink)
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Unread 01-20-2009, 11:58 PM   #9 (permalink)
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I laid them on top of each other and then made the top one semi-transparent.

Though close, they're not identical. Their hypotenuses don't match.

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Unread 01-21-2009, 12:05 AM   #10 (permalink)
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Originally Posted by DDTempest View Post
You're a dipshit, the two triangles don't have the same dimensions. The top figure only looks like a triangle when it actually has four sides.

It's an optical illusion.

It kinda has infinate sides, not sure where you got 4 from.
you should get a pair of these glasses, they help with spotting some asshole tricking you.
he doesn't even say its a triangle.
headset optional

^^
thats what I said.

Last edited by Dent; 05-03-2009 at 04:49 AM.
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Unread 01-21-2009, 12:09 AM   #11 (permalink)
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Nice work, Gaz.

The 4 figures cannot possibly be the same figures in both pictures, as they would require the same amount of space to be taken up and cannot possibly include the addition of the empty box. The slight difference in the diag fulfills all the space left by the lone empty box.
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Unread 01-21-2009, 12:09 AM   #12 (permalink)
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Wow... so instead of this being an interesting mathematical problem, it's a dumb sleight of hand. I'd negrep if I didn't know your intentions were pure, ID.
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Unread 01-21-2009, 12:11 AM   #13 (permalink)
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Good call on holding back the negrep, Dent and f3lix are both wrong fyi.

#YOLO
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Unread 01-21-2009, 12:14 AM   #14 (permalink)
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This example fucking sucks, so does the grainy picture with the fat black lines.
much easier to see with graph paper.

Last edited by Dent; 01-21-2009 at 12:24 AM.
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Unread 01-21-2009, 12:36 AM   #15 (permalink)
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Originally Posted by Dent View Post

This example fucking sucks, so does the grainy picture with the fat black lines.
much easier to see with graph paper.
This is especially evident when looking at how the hypotenuses relates to the intersection points on the grid.

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Unread 01-21-2009, 01:19 AM   #16 (permalink)
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It can be seen that the hypotenuse of the large triangle is not a straight line, here is how you can calculate that:

Right triangles made within larger right triangles [like the green triangle in the overall triangle] have equal angles. So, the interior angles in all the triangles found in the diagram must be equal to each corresponding interior angle [green triangle's angle at the top of both green and overall triangle must equal the red's top most angle]. With other geometric knowledge, red triangle should be similar to green triangle.

We are not given angle measurements, so trigonometry is needed.

We do know the lengths of the legs of each triangle. So the basic trigonometric function of tan A = a/b, where both a and b represent the triangle's legs. We don't know the value of A (the angle) so we will need to use tangent's inverse, arctan [sometimes expressed as 1/tan x or tan x ^-1]

For shorthand, I will use the symbol "#" for an angle.
# = arctan (a/b)

For red triangle and green triangle to be similar, using # = arctan (a/b) must equal each other when used on both triangles.

For green triangle I will use # = arctan (a/b)
For red triangle I will use # = arctan (a'/b')

arctan (a/b) must equal arctan (a'/b') for these triangles to be similar, thus making the overall triangle really a triangle and not a quadrilateral.

Is this equation valid?
Does arctan (a/b) = arctan (a'/b')

arctan (2/5) = arctan (3/8)
after some calculations..
arctan (2/5) does not equal arctan (3/8)

This is means the angles are not equal to each other, meaning the triangles are not similar, meaning the whole triangle is quadrilateral. Because this picture is a quadrilateral and not a triangle, smaller triangles cannot be cut and pasted anywhere to form a solid triangle.

After all this, I feel as if I've used trigonometry wrong and that I am wrong. I haven't taken trig or done math in a while.
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Unread 01-21-2009, 01:22 AM   #17 (permalink)
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Wow... nice fucking work on the solution, LS. Posrepped. Tits now? Haha... just kidding kidding, f3lix.

No but seriously, show us your tits please.
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Unread 01-21-2009, 01:36 AM   #18 (permalink)
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She's a keeper.
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Unread 01-21-2009, 01:40 AM   #19 (permalink)
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Quote:
Originally Posted by Landing Strip View Post
It can be seen that the hypotenuse of the large triangle is not a straight line, here is how you can calculate that:

Right triangles made within larger right triangles [like the green triangle in the overall triangle] have equal angles. So, the interior angles in all the triangles found in the diagram must be equal to each corresponding interior angle [green triangle's angle at the top of both green and overall triangle must equal the red's top most angle]. With other geometric knowledge, red triangle should be similar to green triangle.

We are not given angle measurements, so trigonometry is needed.

We do know the lengths of the legs of each triangle. So the basic trigonometric function of tan A = a/b, where both a and b represent the triangle's legs. We don't know the value of A (the angle) so we will need to use tangent's inverse, arctan [sometimes expressed as 1/tan x or tan x ^-1]

For shorthand, I will use the symbol "#" for an angle.
# = arctan (a/b)

For red triangle and green triangle to be similar, using # = arctan (a/b) must equal each other when used on both triangles.

For green triangle I will use # = arctan (a/b)
For red triangle I will use # = arctan (a'/b')

arctan (a/b) must equal arctan (a'/b') for these triangles to be similar, thus making the overall triangle really a triangle and not a quadrilateral.

Is this equation valid?
Does arctan (a/b) = arctan (a'/b')

arctan (2/5) = arctan (3/8)
after some calculations..
arctan (2/5) does not equal arctan (3/8)

This is means the angles are not equal to each other, meaning the triangles are not similar, meaning the whole triangle is quadrilateral. Because this picture is a quadrilateral and not a triangle, smaller triangles cannot be cut and pasted anywhere to form a solid triangle.

After all this, I feel as if I've used trigonometry wrong and that I am wrong. I haven't taken trig or done math in a while.



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Unread 01-21-2009, 09:33 AM   #20 (permalink)
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Guys, did you see where I put them on top of one another to show that they're different?
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Unread 01-21-2009, 11:35 AM   #21 (permalink)
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Or how I explained that they were different before you put them on top of each other =P
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Unread 01-21-2009, 12:01 PM   #22 (permalink)
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=P
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Unread 01-21-2009, 01:22 PM   #23 (permalink)
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or that I put words to the difference.
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Unread 01-21-2009, 05:53 PM   #24 (permalink)
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I have 4 pictures, thats 4000 words if we're talking science.
Preparing for me +nets now,
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Unread 01-21-2009, 06:59 PM   #25 (permalink)
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A variation on this may have already been said somewhere in this thread, but this is what my friend Lisa's dad had to say about this (he got his PhD in mathematics from Yale and was an actuary for AIG for 20+ years before retiring well before all the shit hit the fan... like the guy has somewhat limited social skills because his mind is so preoccupied with thinking about math... ala Beautiful Mind just w/o the craziness):

As I was saying on the phone, you can tell, for instance, that the upper large triangle is not really a triangle, if it were the upper right acute angles on each of the green and red little triangles would be the same. But the upper acute angle of the green triangle has a tangent (ratio of opposite to adjacent sides) of 5/2=2.5. The red is 8/3=2.666.

But yea, pretty sure others have said something to that effect already.

Last edited by Ugly Bastard; 01-21-2009 at 07:00 PM.
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